-3(x)=4x^2-5

Solution for -3(x)=4x^2-5 equation:

-3(x)=4x^2-5

We move all terms to the left:

-3(x)-(4x^2-5)=0

We get rid of parentheses

-4x^2-3x+5=0

a = -4; b = -3; c = +5;
Δ = b2-4ac
Δ = -32-4·(-4)·5
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{89}}{2*-4}=\frac{3-\sqrt{89}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{89}}{2*-4}=\frac{3+\sqrt{89}}{-8}
$